Area of Composite Figures With Triangles

Have students name each shape and write its formula before they calculate. On the rectilinear and composite pages, ask them to draw the line that splits each shape, and use the word problem page last.

Find the area of 4 composite figures with triangles by splitting or subtracting, like 91.5 square yards. Triangle area = base × height ÷ 2, and a dashed line inside a figure shows a height or a split. The directions on the page read: Find the area of each figure. Split it into rectangles, triangles or trapezoids, or subtract a missing piece. Use the work space. Write exact decimal answers. An answer key is included.

Yes, both. We made it for 6th Grade geometry, and the page works the same whether it lands on a kitchen table or a center rotation. At home, most families go through it together and talk the answers out loud, and that talking is where most of the learning happens with area and perimeter of polygons. In class it runs well as independent work while you pull a small group. Print one copy or thirty, whichever the day needs.

Add the two parallel bases, multiply by the height and take half: A = 1/2 × (b1 + b2) × h. A trapezoid with bases 9 m and 15 m and a height of 8 m has an area of 96 square meters.

Area counts square units straight up from the base, so it needs the perpendicular height. A parallelogram with a base of 9 ft, a height of 8 ft and a slanted side of 10 ft has an area of 72 square feet.

Split it into rectangles and triangles, find each area and add. Ben's deck is a 10 ft by 8 ft rectangle with a triangle point, and the whole deck is 15 ft long, so its area is 80 + 20 = 100 square feet.

Add every side length around the outside. On Area and Perimeter of Rectilinear Shapes, the L shape with sides 9, 3, 5, 5, 4 and 8 cm has a perimeter of 34 cm.